Answer
Each hand supports 230N of weight.
Each foot supports a weight of $1.0*10^1N$
Work Step by Step
Sum the torques about his feet to solve for the force on his hands.
$(+ \circlearrowleft) \sum \tau=0$
$-1.37m*F+68kg*9.8m/s^2*.95m=0$
$F=(68kg*9.8m/s^2*.95m)/(1.37m)$
$F\approx460N$
$460N/2=230N$
Each hand supports $230N$ of weight.
Sum the torques about his hands to solve for the force in his feet
$(+ \circlearrowleft) \sum \tau=0$
$1.37m*F-68kg*9.8m/s^2*.24m=0$
$F=(68kg*9.8m/s^2*.24m)/(1.37m)$
$F\approx200N$
$200N/2=100N$
Each foot supports a weight of $1.0*10^1N$
