Answer
$T\approx6.0*10^1N$
The tension is so large because the small angle means most of the tension acts horizontally.
Work Step by Step
We will sum the forces vertically to solve for the tension in the rope, T.
$(\uparrow +) \sum \overrightarrow{F}_{y} =0 $
$2*T*sin3.5^{\circ}-mg=0$
$T=\frac{mg}{2*sin3.5^{\circ}}$
$T=\frac{0.75kg*9.8m/s^2}{2*sin3.5^{\circ}}$
$T\approx6.0*10^1N$
The tension is so large because the small angle means most of the tension acts horizontally.
