Answer
$F_N=120N$
Work Step by Step
$\theta=\arctan(\frac{2.0m}{2.6m})=37.6^o$
$F_{Wx}=(115N)\cos(37.6^o)=91.2N$
$\phi=\frac{60^o}{2}=30^o$
$F_N=2\times (115N)\sin(37.6^o)\cos(30^o)=120N$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 254: 26
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