Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 252: 7


The maximum weight of the chandelier is 1170N

Work Step by Step

To find the max weight of the chandelier, we will set the cords to their maximum allowable tension given, 1660N, and then sum the forces vertically. Let W be the weight of the chandelier. Let T be the tension in the cord. Therefore; $(\uparrow +) \sum \overrightarrow{F}_{y} =0 $ $-W+sin(45^{\circ})*T=0$ $W=sin(45^{\circ})*T$ $W=sin(45^{\circ})*1660N$ $W\approx1170N$
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