Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 252: 3

Answer

A) The counterweight needs to be 2.3m away from the crane. B) The maximum load that can be lifted is 4200kg.

Work Step by Step

Part A) Let x be the distance between the counterweight and the crane. To determine the distance, we will sum the torques about any point on the main crane shaft; $(+ \circlearrowleft) \sum\tau=0$ $9500kg*x-2800kg*7.7m=0$ $x=\frac{2800kg*7.7m}{9500kg}$ $x\approx2.3m$ The counterweight needs to be 2.3m away from the crane. Part B) We set x to be 3.4m and then solve for the maximum load possible by again summing the torques about the crane. Let M be the mass of the load to be lifted. $(+ \circlearrowleft) \sum\tau=0$ $9500kg*3.4m-7.7m*M=0$ $M=\frac{9500kg*3.4m}{7.7m}$ $M\approx4200kg$ The maximum load that can be lifted is 4200kg.
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