## Physics: Principles with Applications (7th Edition)

1) Finding x-component of the force $(\rightarrow +) \sum \overrightarrow{F}_{x} =0$ $395N-\cos(75^{\circ})485N + \overrightarrow{F}_{x}=0$ $\overrightarrow{F}_{x}= -395N+\cos(75^{\circ})485N$ $\overrightarrow{F}_{x}\approx-252N$ 2)Finding the y-component $(\uparrow +) \sum \overrightarrow{F}_{y} =0$ $\sin(75^{\circ})475N + \overrightarrow{F}_{y}=0$ $\overrightarrow{F}_{y}=-\sin(75^{\circ})475N$ $\overrightarrow{F}_{y}\approx-459N$ 3) Finding the magnitude of \overrightarrow{F} $\Vert\overrightarrow{F}\Vert=\sqrt {F^2_x+F^2_y}$ $\Vert\overrightarrow{F}\Vert\approx\sqrt {(-252N)^2+(-459N)^2}$ $\Vert\overrightarrow{F}\Vert\approx528N$ 3) Finding the direction $\arctan{F_y/F_x}\approx60^{\circ}$ $180^{\circ}+60^{\circ}=120^{\circ}$ 120 degrees clockwise from force A