Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 252: 2

Answer

The mass needed to support the leg is 6.73kg.

Work Step by Step

We will sum the torque at the hip to find the mass, m; $(+\circlearrowleft) \sum\tau=0$ $35cm*15kg*9.8m/s^2-m*9.8m/s^2*78cm=0$ $m=\frac{35cm*15kg*9.8m/s^2}{9.8m/s^2*78cm}$ $m\approx6.73kg$ Therefore, the mass needs to be 6.73kg
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