Answer
(a) $a = 3.67 ~m/s^2$
(b) v = 9.39 m/s
Work Step by Step
(a) We can use the force equation to find the acceleration.
$ma = \sum ~F$
$ma = mg ~sin(\theta)$
$a = g ~sin(\theta) = (9.80 ~m/s^2)\cdot ~sin(22.0^{\circ})$
$a = 3.67 ~m/s^2$
(b) $v^2 = v_0^2 + 2ax = 0 + 2ax$
$v = \sqrt{2ax} = \sqrt{(2)(3.67 ~m/s^2)(12.0 ~m)} = 9.39 ~m/s$
