Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 104: 53

Answer

t = 4.8 seconds

Work Step by Step

We can use a force equation to find the acceleration: $\sum ~F = ma$ $mg ~sin(\theta) - mg ~cos(\theta)\cdot \mu_k = ma$ $a = g ~sin(\theta) - g ~cos(\theta)\cdot \mu_k$ $a = (9.80 ~m/s^2)\sin(8.0) - (9.80 ~m/s^2) ~cos(8.0)\cdot (0.060)$ $a = 0.78 ~m/s^2$ We can use the acceleration to find the time to slide down. $x = \frac{1}{2}at^2$ $t = \sqrt{\frac{2x}{a}} = \sqrt{\frac{(2)(9.0 ~m)}{0.78 ~m/s^2}} = 4.8~s$ It takes 4.8 seconds for the bar of soap to slide down to the bottom of the ramp.
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