Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 62

Answer

n=13700. $E_{n}=-7.19\times10^{-8}eV$

Work Step by Step

Calculate the value of n is using $r_n=n^2r_1$. $$n=\sqrt{\frac{r_n}{r_1}}=\sqrt{\frac{1.00\times10^{-2}m}{0.529\times10^{-10}m}}=13749\approx13700$$ Now find the energy using equation 27–15b with Z = 1 and the n we just calculated. $$E_{n}=\frac{-13.6eV(Z^2)}{n^2}$$ $$E_{n}=\frac{-13.6eV(1^2)}{13749^2}=-7.19\times10^{-8}eV$$
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