Answer
1.51 eV
Work Step by Step
Ionizing the H atom means removing the electron. This is the same as raising the electron to zero energy.
$$E_{ionization}=0-E_3=0-\frac{-13.6eV}{3^2}=1.51eV$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 50
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