Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 38

Answer

$3.2\times10^{-32}m$

Work Step by Step

We find the wavelength using equation 27–8. $$\lambda=\frac{h}{p}=\frac{h}{mv}$$ $$\lambda=\frac{6.63\times10^{-34}J \cdot s }{(0.21kg)(0.10m/s)}=3.2\times10^{-32}m$$
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