Answer
$\frac{KE_e}{KE_p}=1830$
Work Step by Step
The particles are not relativistic, so $KE=\frac{p^2}{2m}$.
$$KE=\frac{p^2}{2m}$$
Use equation 27–8.
$$KE=\frac{h^2}{2m\lambda^2}$$
Form the desired ratio of the kinetic energies. The wavelengths are equal.
$$\frac{KE_e}{KE_p}=\frac{m_p}{m_e}$$
$$\frac{KE_e}{KE_p}=\frac{1.67\times10^{-27}kg}{9.11\times10^{-31}kg}=1830$$
