Answer
5600 kelvin
Work Step by Step
Use Wien’s law, equation 27–2.
$$T=\frac{2.90\times10^{-3}m \cdot K}{\lambda_p}$$
$$T=\frac{2.90\times10^{-3}m \cdot K}{520\times10^{-9}m}=5577K\approx 5600K$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 799: 4
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