Answer
a. $v=7.23\times10^6m/s$
b. $r=1.58cm$
Work Step by Step
a. The electric force, qE, balances the magnetic force, qvB, so v = E/B.
$$v=\frac{E}{B}=\frac{1.88\times10^4V/m}{2.60\times10^{-3}T}=7.23\times10^6m/s$$
b. Use the expression derived in Example 20–6, on page 567, for a charged particle moving in a magnetic field.
$$r=\frac{mv}{qB}$$
$$r=\frac{(9.11\times10^{-31}kg)( 7.23\times10^6m/s)}{(1.60\times10^{-19}C)( 2.60\times10^{-3}T)}$$
$$r=1.58cm$$
