Answer
$6.2\times10^4\frac{C}{kg}$
Work Step by Step
This is the experiment that is described by equation 27–1.
$$\frac{e}{m}=\frac{E}{B^2r}$$
$$=\frac{640V/m}{(0.86T)^2(0.014m)}=6.2\times10^4\frac{C}{kg}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 799: 1
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
