Answer
$1.14\times10^{-27}kg \cdot m/s$
Work Step by Step
Use equation 27–6.
$$p=\frac{h}{\lambda}=\frac{6.63\times10^{-34}J \cdot s }{5.80\times10^{-7}m}$$
$$=1.14\times10^{-27}kg \cdot m/s$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 799: 13
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