Answer
The mass loss is $5.38\times10^{-12}kg$, which is $1.49\times10^{-8}\%$ of the total original mass.
Work Step by Step
Calculate the mass loss using equation 26–8.
$$\Delta m = \frac{\Delta E}{c^2}=\frac{484\times10^3 J}{(3.00\times10^8 m/s)^2}=5.38\times10^{-12}kg$$
The mass of 2 moles of hydrogen molecules and 1 mole of oxygen molecules is $36.0\times10^{-3}kg$.
Find the mass lost as a percentage of the original mass.
$$\frac{5.38\times10^{-12}kg }{36.0\times10^{-3}kg }=1.49\times10^{-10}=1.49\times10^{-8}\%$$
The mass loss is $5.38\times10^{-12}kg$, which is $1.49\times10^{-8}\%$ of the total original mass.
