Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - General Problems - Page 769: 61

Answer

0.79 MeV

Work Step by Step

The rest energy of the 3 product particles is less than the rest energy of the neutron. The kinetic energy arises from the decrease in rest energy. $$KE=m_nc^2-( m_pc^2+ m_ec^2+ m_{\nu}c^2)$$ $$KE=939.57MeV-(938.27MeV+0.511MeV+ 0)=0.79MeV$$
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