Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - General Problems - Page 769: 60

Answer

$2.6\times10^{-5}g$

Work Step by Step

The power (wattage) multiplied by the time is the energy. The mass is found by using equation 26–7. $$E=Pt=mc^2$$ $$m=\frac{Pt}{c^2}=\frac{(75W)(3.16\times10^7s)}{(3.00\times10^8m/s)^2}\frac{1000g}{kg}$$ $$=2.6\times10^-5g $$
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