Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - General Problems - Page 769: 59

Answer

1.022 MeV

Work Step by Step

The minimum amount of electromagnetic energy required would create the pair at rest, with kinetic energy equal to zero. The energy required is their rest energy. Use equation 26–7. Their masses are identical. $$E=2mc^2=2(0.511MeV)=1.022MeV$$
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