Answer
a. $1.3\times10^{-7}F$
b. 36.6A
Work Step by Step
a. Equation 21-19 gives the resonant frequency.
$$f_o=\frac{1}{2 \pi}\sqrt{\frac{1}{LC}}$$
$$C=\frac{1}{4\pi^2Lf_o^2}$$
$$C=\frac{1}{4\pi^2(0.0148H)(3600Hz)^2}=1.3\times10^{-7}F$$
b. As discussed in section 21-15, at resonance the impedance Z is just the resistance R. Find the current by using Ohm’s law.
$$I_{peak}=\frac{V_{peak}}{R}=\frac{150V}{4.10\Omega}=36.6A$$
