Answer
16k $\Omega$
$1.47\times10^{-2}A$
Work Step by Step
Find the answer using equation 21–11b, which gives the reactance of an inductor.
$$X_L=2 \pi f L$$
$$=2 \pi (10.0\times10^3Hz)(0.260H)=16k\Omega$$
Find the current using Ohm’s Law.
$$I=\frac{V}{X_L}$$
$$I=\frac{240V}{2 \pi (10.0\times10^3Hz)(0.260H)}=1.47\times10^{-2}A$$
