Answer
See answers.
Work Step by Step
Use equation 21–15, without an inductive reactance. The capacitor’s reactance is given by equation 21–12b.
a.
$$Z=\sqrt{R^2+X_C^2}=\sqrt{R^2+\frac{1}{4\pi^2 f^2 C^2}}$$
$$Z=\sqrt{(3.5\times10^3 \Omega)^2+\frac{1}{4\pi^2 (60Hz)^2 (3.0\times10^{-6}F)^2}}=3.6\times10^3\Omega $$
b.
$$Z=\sqrt{R^2+X_C^2}=\sqrt{R^2+\frac{1}{4\pi^2 f^2 C^2}}$$
$$Z=\sqrt{(3.5\times10^3 \Omega)^2+\frac{1}{4\pi^2 (60\times10^3 Hz)^2 (3.0\times10^{-6}F)^2}}=3.5\times10^3\Omega $$
