Answer
$5.22\times10^{-2}H$
Work Step by Step
Start with equation 21–11b, which gives the reactance of an inductor.
$$X_L=2 \pi f L$$
Find the current using Ohm’s Law.
$$I=\frac{V}{X_L}=\frac{V}{2 \pi f L }$$
Now, solve for the inductance.
$$L=\frac{V}{2 \pi f I}$$
$$=\frac{240V}{2 \pi (60.0Hz)(12.2A)}=5.22\times10^{-2}H$$
