Answer
a. 1.1 A
b. 110$\Omega$
Work Step by Step
a. Use equation 18–5 to calculate the power, and solve for the current I.
$$P=IV$$
$$I=\frac{P}{V}=\frac{130W}{120V}=1.1A$$
b. Use equation 18–6b to calculate the power, and solve for the resistance R.
$$P=\frac{V^2}{R}$$
$$R=\frac{V^2}{P}=\frac{(120V)^2}{130W}=110\Omega$$
