Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 522: 28

Answer

$17.5\Omega$

Work Step by Step

Use equation 18–6b to calculate the power, and solve for the resistance R. $$P=\frac{V^2}{R}$$ $$R=\frac{V^2}{P}=\frac{(240V)^2}{3300W}=17.5\Omega$$
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