Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 522: 29

Answer

31 volts

Work Step by Step

Use equation 18–6b to calculate the power, and solve for the voltage V. $$P=\frac{V^2}{R}$$ $$V=\sqrt{PR}=\sqrt{(0.25W)(3900\Omega)}=31V$$ If the voltage is any higher than this, the power will exceed 0.25 watts.
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