Answer
$T=47.6^{\circ}C$
Work Step by Step
We know that:
$R=R_{\circ}[1+\alpha(T-T_{\circ})]$
This can be rearranged as
$T=T_{\circ}+\frac{1}{\alpha}(\frac{R}{R_{\circ}}-1)$
But we know also know that
$R=\frac{V}{I}$
$\implies T=T_{\circ}+\frac{1}{\alpha}(\frac{\frac{V}{I}}{\frac{V}{I_{\circ}}}-1)$
This simplifies to
$T=T_{\circ}+\frac{1}{\alpha}(\frac{I_{\circ}}{I}-1)$
We plug in the known values to obtain:
$T=23.5^{\circ}+\frac{1}{0.00429}\times(\frac{0.4212}{0.3818}-1)=47.6^{\circ}C$
