Answer
$1.1\times10^{-6}C$
Work Step by Step
Use the definition of capacitance with equation 17–8 for the capacitance of a parallel-plate capacitor.
Assume the the shoe bottom is 25 cm by 8 cm, with an area of 200 square cm.
$$Q=CV= \epsilon_o \frac{A}{d}V $$
$$=(8.85\times10^{-12}C^2/(N\cdot m^2)) \frac{200\times10^{-4}m^2}{0.001m}(6.0\times10^3V) $$
$$=1.1\times10^{-6}C$$
Your answer may vary, depending on your estimate of the shoe area.
