Answer
a. 31J
b. $5.9\times10^5W$
Work Step by Step
a. The stored energy is found using equation 17–10.
$$PE=\frac{1}{2}CV^2=\frac{1}{2}(5.0\times10^{-8}F)(3.5\times10^4V)^2\approx 31J$$
b. The power is the energy delivered per unit time.
$$P=\frac{0.12(30.625J)}{6.2\times10^{-6}s}=5.9\times10^5W$$
