Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 17 - Electric Potential - General Problems - Page 499: 77

Answer

a) 17cm from negative charge opposite positive charge b) 1.1cm from negative charge toward positive charge 8.1cm from negative charge away from positive charge

Work Step by Step

a) $k(\frac{3.4\mu C}{r_1^2}+\frac{-2.6\mu C}{r_2^2})=0$ $r_2=\sqrt{\frac{2.6}{3.4}}r_1$ $r_1-r_2=0.025m$ $r_1=0.199m$ $r_2=0.174m$ 17cm from negative charge opposite positive charge b) $k(\frac{3.4\mu C}{r_1}+\frac{-2.6\mu C}{r_2})=0$ $r_2=\frac{2.6r_1}{3.4}$ $r_1+r_2=0.025m$ $1.76r_1=0.025m$ $r_1=0.014m$ $r_2=0.011m$ 1.1cm from negative charge toward positive charge $r_1-r_2=0.025m$ $r_2=\frac{2.6r_1}{3.4}$ $r_1=0.106m$ $r_2=0.081m$ 8.1cm from negative charge away from positive charge
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