Answer
a) $-2.9\times10^5V$
b) $-2.5\times10^6N/C$
Work Step by Step
a) $k(\frac{3.5\mu C}{0.115m}+\frac{-7.2\mu C}{0.115m})=-2.9\times10^5V$
b) $k(\frac{3.5\mu C}{(0.115m)^2}+\frac{-7.2\mu C}{(0.115m)^2})=-2.5\times10^6N/C$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 17 - Electric Potential - General Problems - Page 499: 84
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