Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 16 - Electric Charge and Electric Field - Problems - Page 469: 8

Answer

$1.75 \times 10^{14}$ $electrons$ $1.59 \times 10^{-16} kg$

Work Step by Step

Firstly to get the number of electrons, divide 28µC by e, that is, $1.6 \times 10^{-19}C$: $2.8 \times 10^{-5}C \div (1.6 \times 10^{-19}C) = 1.75 \times 10^{14}$ Then multiply the number of electrons with the mass of one electron, $9.1 \times 10^{-31}$: $1.75 \times 10^{14} \times9.1 \times 10^{-31}kg = 1.59 \times 10^{-16}kg$
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