Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 16 - Electric Charge and Electric Field - Problems - Page 469: 5

Answer

$1.9 \times 10^{-13}$%

Work Step by Step

Because the comb is charged to 3.0µC, it lost 3.0µC electrons. ∵$e = 1.6^{-19} C$ ∴$M_{lost-electrons} = 3.0µC \div 1.6^{-19} C \times 9.1 \times 10^{-31}kg = \frac{3.0 \times 10^{-6}C}{1.6^{-19} C} \times 9.1 \times 10^{-31}kg = 1.7 \times 10^{-17} kg = 1.7 \times 10^{-14} g$ ∴The change of mass = $\frac{1.7 \times 10^{-14} g}{9.0g} \times$ 100% = $1.9 \times 10^{-13}$%
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