Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 16 - Electric Charge and Electric Field - Problems - Page 469: 19

Answer

$3.94\times10^{-16}\;N \;west$

Work Step by Step

Use equation 16–3 to calculate the direction and magnitude of the force. A negative charge feels a force in the direction opposite to the local electric field. $$\vec{E}=\frac{\vec{F}}{q}$$ $$\vec{F}=q\vec{E}=(-1.602\times10^{-19}C)(2460\;N/C\;east)$$ $$= (3.94\times10^{-16}\;N \;west)$$
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