Answer
$3 \times 10^{14}$
Work Step by Step
∵$e = 1.6\times10^{-19} C$
∴the charge of one electron is $-e = -1.6\times10^{-19} C$
∵$1µC = 10^{-6} C$
∴$-48.0µC = -48 \times 10^{-6} C$
To know how many -e is in -48.0µC, we need to divide -48.0µC by -e
∴The number of electrons in -48.0µC = $\frac{-48 \times 10^{-6} C}{-1.6\times10^{-19} C} = 3 \times 10^{14}$
