Answer
$6.0\times10^6J$
Work Step by Step
Use equation 14–2. One liter of water has a mass of 1 kg.
$$Q=mc\Delta T=(18kg)(\frac{4186J}{kg\cdot C^{\circ}})(95^{\circ}C-15^{\circ}C)=6.0\times10^6J$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 14 - Heat - Problems - Page 408: 9
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