Answer
a. $1.0\times 10^7J$
b. $2.9kWh$
c. 29 cents
Work Step by Step
a. $(2500 Cal) (\frac{4186J}{1Cal})\approx1.0\times 10^7J$
b. $(2500 Cal) (\frac{1kWh}{860Cal})=2.9kWh$
c. At 10 cents per kWh, 2.9 kWh costs about 29 cents. In the United States, this amount of money would be insufficient to feed yourself.
