Answer
$4.5\times10^5J$ or $110kcal$
Work Step by Step
The car’s initial kinetic energy is transformed into thermal energy.
$$Q=\frac{1}{2}mv^2=\frac{1}{2}(1300kg)(\frac{95000m}{3600s})^2\approx 4.5\times10^5J$$
$$Q=(4.526\times10^5J)(\frac{1kcal}{4186J})\approx 110kcal$$
