Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 354: 20

Answer

(a) $P = 9.4\times 10^{-6}~W$ (b) We would need 6.4 million people to produce 60 W of normal conversation.

Work Step by Step

We can find the power output of a person speaking in normal conversation. Using Table 12-2, we can let the intensity be $3\times 10^{-6}~W/m^2$ and we can let the radius be $R = 0.50~m$. $P = I~A$ $P = I~(4\pi~R^2)$ $P = (3\times 10^{-6}~W/m^2)(4\pi)(0.50~m)^2$ $P = 9.4\times 10^{-6}~W$ (b) We can find the number of people $N$ required to produce 60 W of normal conversation. $N = \frac{60~W}{9.4\times 10^{-6}~W}$ $N = 6.4\times 10^6~people$ We would need 6.4 million people to produce 60 W of normal conversation.
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