Answer
82 dB = $1.6 \times 10^8$
98 dB = $6.3 \times 10^9$
Work Step by Step
Calculate the ratio for the 82-dB CD player.
$$82 dB=10log\frac{I_s}{I_n}$$
$$\frac{I_s}{I_n}=10^{8.2}=1.6 \times 10^8$$
Next, for the other CD player.
$$98 dB=10log\frac{I_s}{I_n}$$
$$\frac{I_s}{I_n}=10^{9.8}=6.3 \times 10^9$$
