Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 12 - Sound - Problems - Page 354: 3

Answer

a. 0.017 m to 17 m b. $1.9 \times 10^{-5} m$

Work Step by Step

The wave speed is given by $v=\lambda f$. a. The minimum wavelength corresponds to the maximum frequency, and vice versa. $$\lambda_{min}=\frac{v}{f_{max}}=\frac{343 m/s}{20000 Hz}\approx 0.017 m$$ $$\lambda_{max}=\frac{v}{f_{min}}=\frac{343 m/s}{20 Hz}\approx 17 m$$ b. $\lambda_{ultrasonic}=\frac{v}{f}=\frac{343 m/s}{18 \times 10^6 Hz}\approx 1.9 \times 10^{-5} m$
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