Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 33 - Wave Optics - Exercises and Problems - Page 955: 7


0.22 mm

Work Step by Step

Given: $\lambda=589\,nm=589\times10^{-9}\,m$ $D=150\,cm=150\times10^{-2}\,m$ $\beta=4.0\,mm=4.0\times10^{-3}\,m$ Recall: $\beta=\frac{\lambda D}{d}$ or $d=\frac{\lambda D}{\beta}$ Result: $d=\frac{589\times10^{-9}\,m\times150\times10^{-2}\,m}{4.0\times10^{-3}\,m}=0.00022\,m=0.22\,mm$
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