Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 33 - Wave Optics - Exercises and Problems - Page 955: 17

Answer

$L = 1.2~m$

Work Step by Step

We can find the distance to the screen: $w = \frac{2~\lambda~L}{d}$ $L = \frac{w~d}{2~\lambda}$ $L = \frac{(0.010~m)(0.15\times 10^{-3}~m)}{(2)(630\times 10^{-9}~m)}$ $L = 1.2~m$
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