Answer
$y_1 = 18.2~mm$
Work Step by Step
We can write an expression for the first secondary maximum:
$y_{max,1} = \frac{1.43~\lambda~L}{d} = 26~mm$
We can find the position of the first minimum:
$y_1 = \frac{\lambda~L}{d}$
$y_1 = \frac{\lambda~L}{d} = \frac{26~mm}{1.43}$
$y_1 = 18.2~mm$