Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 33 - Wave Optics - Exercises and Problems - Page 955: 22


$y_1 = 18.2~mm$

Work Step by Step

We can write an expression for the first secondary maximum: $y_{max,1} = \frac{1.43~\lambda~L}{d} = 26~mm$ We can find the position of the first minimum: $y_1 = \frac{\lambda~L}{d}$ $y_1 = \frac{\lambda~L}{d} = \frac{26~mm}{1.43}$ $y_1 = 18.2~mm$
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