## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$w = 4.0~mm$
We can find the width of the central maximum: $w = \frac{2~\lambda~L}{d}$ $w = \frac{(2)(500\times 10^{-9}~m)(2.0~m)}{0.50\times 10^{-3}~m}$ $w = 4.0\times 10^{-3}~m$ $w = 4.0~mm$