Answer
$w = 4.0~mm$
Work Step by Step
We can find the width of the central maximum:
$w = \frac{2~\lambda~L}{d}$
$w = \frac{(2)(500\times 10^{-9}~m)(2.0~m)}{0.50\times 10^{-3}~m}$
$w = 4.0\times 10^{-3}~m$
$w = 4.0~mm$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 33 - Wave Optics - Exercises and Problems - Page 955: 18
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
