Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 33 - Wave Optics - Exercises and Problems - Page 955: 18


$w = 4.0~mm$

Work Step by Step

We can find the width of the central maximum: $w = \frac{2~\lambda~L}{d}$ $w = \frac{(2)(500\times 10^{-9}~m)(2.0~m)}{0.50\times 10^{-3}~m}$ $w = 4.0\times 10^{-3}~m$ $w = 4.0~mm$
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