Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 32 - AC Circuits - Exercises and Problems - Page 924: 8

Answer

(a) $I_0 = 1.88~mA$ (b) $I_0 = 1.88~A$

Work Step by Step

We can write an expression for the peak current: $I_0 = \omega ~C~\epsilon_0 = 2\pi~f ~C~\epsilon_0$ (a)We can find the peak current: $I_0 = 2\pi~f ~C~\epsilon_0$ $I_0 = (2\pi)~(100~Hz) (0.30\times 10^{-6}~F)~(10.0~V)$ $I_0 = 1.88\times 10^{-3}~A$ $I_0 = 1.88~mA$ (b) We can find the peak current: $I_0 = 2\pi~f ~C~\epsilon_0$ $I_0 = (2\pi)~(100\times 10^3~Hz) (0.30\times 10^{-6}~F)~(10.0~V)$ $I_0 = 1.88~A$
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