Answer
(a) $I_0 = 20~mA$
(b) $I_0 = 20~mA$
Work Step by Step
We can write an expression for the peak current:
$I_0 = \omega ~C~\epsilon_0 = 2\pi~f ~C~\epsilon_0$
(a) If the emf frequency $f$ is doubled then the peak current increases by a factor of $2$
$I_0 = 20~mA$
(b) If the peak emf $\epsilon_0$ is doubled then the peak current increases by a factor of $2$
$I_0 = 20~mA$
