Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 32 - AC Circuits - Exercises and Problems - Page 924: 16


$C = 1.59\times 10^{-6}~F$

Work Step by Step

We can find the value of the capacitor: $f = \frac{1}{2\pi ~R~C}$ $C = \frac{1}{2\pi ~R~f}$ $C = \frac{1}{(2\pi) ~(100 ~\Omega)~(1000~Hz)}$ $C = 1.59\times 10^{-6}~F$
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